In other news, let’s go back here:
This study:
The frequencies of the AB0 and RH blood group alleles and heterozygosity indices were determined for the populations of two large industrial cities of Gorlovka and Mariupol. In the population of Gorlovka the gene frequencies were as follows: AB0*0 = 0.576, AB0*A = 0.266, AB0*B = 0.158, and RH*D = 0.592, in Mariupol the frequencies were AB0*0 = 0.584, AB0*A = 0.265, AB0*B = 0.151, and RH*D = 0.604. In Gorlovka the heterozygosity indices in respect to the AB0 and RH alleles were 0.572 and 0.483, respectively; in Mariupol, 0.566 and 0.478, respectively. There were no statistically significant differences between the two populations in respect to the genetic markers analyzed. However, the heterozygosity values obtained were more similar to the corresponding estimates for some populations of Russia, than for the total population of the Ukraine.
https://pubmed.ncbi.nlm.nih.gov/12760254/
… and apply this formula:
In example 1: RH*D = 0.592 = p
We need to find q being the gene frequency of Rh(d) with q^2 being the Rh negative frequency.
0.592^2+2×0.592q+q^2=1
q^2+1.184q-0.649536=0
q=0.408
That is the Rh(d) gene frequency.
q^2=0.166464
That makes the Rh negative phenotype frequency in example 1
16.6464% Rh negative
If we round it up, we get 17%.
In example 2, this time making it easier using the heterozygote frequency, we have:
0.604^2+ 0.478+q^2=1
q^2=0.157184
… so the Rh negative frequency there is at around 16%